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MaluKrooomer - 17 Dec 2010
%$A$%
%\[ g(B)-g(0) = \frac{e^2}{\pi h} \left[ F\left(\frac{\tau_B^{-1}}{\tau_\phi^{-1}}\right) - F\left(\frac{\tau_B^{-1}}{\tau_\phi^{-1} + 2\tau_i^{-1}}\right) - 2 F\left(\frac{\tau_B^{-1}}{\tau_\phi^{-1}+\tau_i^{-1}+\tau_*^{-1}}\right) \right] \]%
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Topic revision:
17 Dec 2010, MaluKrooomer
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